Metadata acl_grantee_count_per_table
Metadata benchmark · all Metadata queries
Representative SQL
Rendered in the benchmark’s native SQL with default parameters (no dialect translation available).
SELECT table_name, COUNT(DISTINCT grantee) AS grantee_count, COUNT(*) AS total_grantsFROM information_schema.table_privilegesWHERE NOT table_schema IN ('information_schema', 'pg_catalog')GROUP BY table_nameORDER BY grantee_count DESCLIMIT 20Representative DataFrame
No DataFrame implementation is registered for this query.
Get the exact query for your run
The blocks above are representative. To get the precise statement a specific platform runs at a specific scale, substitute your own values:
from benchbox import MetadataPrimitives
bench = MetadataPrimitives(scale_factor=1.0) # your scale factorprint(bench.get_queries()['acl_grantee_count_per_table'])Source
Query text: benchbox/core/metadata_primitives/queries.py