Metadata acl_privilege_summary
Metadata benchmark · all Metadata queries
Representative SQL
Rendered in the benchmark’s native SQL with default parameters (no dialect translation available).
SELECT privilege_type, COUNT(*) AS total_grants, COUNT(DISTINCT grantee) AS distinct_grantees, COUNT(DISTINCT table_name) AS distinct_tablesFROM information_schema.table_privilegesWHERE NOT table_schema IN ('information_schema', 'pg_catalog')GROUP BY privilege_typeORDER BY total_grants DESCRepresentative DataFrame
No DataFrame implementation is registered for this query.
Get the exact query for your run
The blocks above are representative. To get the precise statement a specific platform runs at a specific scale, substitute your own values:
from benchbox import MetadataPrimitives
bench = MetadataPrimitives(scale_factor=1.0) # your scale factorprint(bench.get_queries()['acl_privilege_summary'])Source
Query text: benchbox/core/metadata_primitives/queries.py